10(x+4)8x-(x+2)=10(x+4)8x-(x+2)

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Solution for 10(x+4)8x-(x+2)=10(x+4)8x-(x+2) equation:



10(x+4)8x-(x+2)=10(x+4)8x-(x+2)
We move all terms to the left:
10(x+4)8x-(x+2)-(10(x+4)8x-(x+2))=0
We multiply parentheses
80x^2+320x-(x+2)-(10(x+4)8x-(x+2))=0
We get rid of parentheses
80x^2+320x-x-(10(x+4)8x-(x+2))-2=0
We calculate terms in parentheses: -(10(x+4)8x-(x+2)), so:
10(x+4)8x-(x+2)
We multiply parentheses
80x^2+320x-(x+2)
We get rid of parentheses
80x^2+320x-x-2
We add all the numbers together, and all the variables
80x^2+319x-2
Back to the equation:
-(80x^2+319x-2)
We add all the numbers together, and all the variables
80x^2+319x-(80x^2+319x-2)-2=0
We get rid of parentheses
80x^2-80x^2+319x-319x+2-2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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