10(x+4)=41+9x

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Solution for 10(x+4)=41+9x equation: 



10(x+4)=41+9x

We move all terms to the left:

10(x+4)-(41+9x)=0

We add all the numbers together, and all the variables

10(x+4)-(9x+41)=0

We multiply parentheses

10x-(9x+41)+40=0

We get rid of parentheses

10x-9x-41+40=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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