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10(x+5)=20(2x-3)
We move all terms to the left:
10(x+5)-(20(2x-3))=0
We multiply parentheses
10x-(20(2x-3))+50=0
We calculate terms in parentheses: -(20(2x-3)), so:We get rid of parentheses
20(2x-3)
We multiply parentheses
40x-60
Back to the equation:
-(40x-60)
10x-40x+60+50=0
We add all the numbers together, and all the variables
-30x+110=0
We move all terms containing x to the left, all other terms to the right
-30x=-110
x=-110/-30
x=3+2/3
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