10(x+5)=20(2x-3)

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Solution for 10(x+5)=20(2x-3) equation: 



10(x+5)=20(2x-3)

We move all terms to the left:

10(x+5)-(20(2x-3))=0

We multiply parentheses

10x-(20(2x-3))+50=0



We calculate terms in parentheses: -(20(2x-3)), so:

20(2x-3)

We multiply parentheses

40x-60

Back to the equation:

-(40x-60)



We get rid of parentheses

10x-40x+60+50=0

We add all the numbers together, and all the variables

-30x+110=0

We move all terms containing x to the left, all other terms to the right

-30x=-110

x=-110/-30

x=3+2/3

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