10(x-1)=5(2x-2)

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Solution for 10(x-1)=5(2x-2) equation:


Simplifying
10(x + -1) = 5(2x + -2)

Reorder the terms:
10(-1 + x) = 5(2x + -2)
(-1 * 10 + x * 10) = 5(2x + -2)
(-10 + 10x) = 5(2x + -2)

Reorder the terms:
-10 + 10x = 5(-2 + 2x)
-10 + 10x = (-2 * 5 + 2x * 5)
-10 + 10x = (-10 + 10x)

Add '10' to each side of the equation.
-10 + 10 + 10x = -10 + 10 + 10x

Combine like terms: -10 + 10 = 0
0 + 10x = -10 + 10 + 10x
10x = -10 + 10 + 10x

Combine like terms: -10 + 10 = 0
10x = 0 + 10x
10x = 10x

Add '-10x' to each side of the equation.
10x + -10x = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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