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10(x-2)(3x+7)=0
We multiply parentheses ..
10(+3x^2+7x-6x-14)=0
We multiply parentheses
30x^2+70x-60x-140=0
We add all the numbers together, and all the variables
30x^2+10x-140=0
a = 30; b = 10; c = -140;
Δ = b2-4ac
Δ = 102-4·30·(-140)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16900}=130$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-130}{2*30}=\frac{-140}{60} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+130}{2*30}=\frac{120}{60} =2 $
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