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10(x-2)=-2(4/3+7x)
We move all terms to the left:
10(x-2)-(-2(4/3+7x))=0
Domain of the equation: 3+7x))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
7x))!=-3
x!=-3/1
x!=-3
x∈R
10(x-2)-(-2(+7x+4/3))=0
We multiply parentheses
10x-(-2(+7x+4/3))-20=0
We multiply all the terms by the denominator
10x*3))-(-2(+7x+4-20*3))=0
We add all the numbers together, and all the variables
10x*3))-(-2(7x-56))=0
We add all the numbers together, and all the variables
10x*3))-(-2(7x=0
Wy multiply elements
30x^2=0
a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{60}=0$
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