10(x-2)=10(3x+8)

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Solution for 10(x-2)=10(3x+8) equation: 



10(x-2)=10(3x+8)

We move all terms to the left:

10(x-2)-(10(3x+8))=0

We multiply parentheses

10x-(10(3x+8))-20=0



We calculate terms in parentheses: -(10(3x+8)), so:

10(3x+8)

We multiply parentheses

30x+80

Back to the equation:

-(30x+80)



We get rid of parentheses

10x-30x-80-20=0

We add all the numbers together, and all the variables

-20x-100=0

We move all terms containing x to the left, all other terms to the right

-20x=100

x=100/-20

x=-5

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