10(x-2)=2(4/3+7x)

Solution for 10(x-2)=2(4/3+7x) equation:

10(x-2)=2(4/3+7x)

We move all terms to the left:

10(x-2)-(2(4/3+7x))=0


Domain of the equation: 3+7x))!=0

We move all terms containing x to the left, all other terms to the right

7x))!=-3

x!=-3/1

x!=-3

x∈R


We add all the numbers together, and all the variables

10(x-2)-(2(+7x+4/3))=0

We multiply parentheses

10x-(2(+7x+4/3))-20=0

We multiply all the terms by the denominator


10x*3))-(2(+7x+4-20*3))=0

We add all the numbers together, and all the variables

10x*3))-(2(7x-56))=0

We add all the numbers together, and all the variables

10x*3))-(2(7x=0

Wy multiply elements

30x^2=0

a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{60}=0$