10(x-2)=2-(x+5)

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Solution for 10(x-2)=2-(x+5) equation: 



10(x-2)=2-(x+5)

We move all terms to the left:

10(x-2)-(2-(x+5))=0

We multiply parentheses

10x-(2-(x+5))-20=0



We calculate terms in parentheses: -(2-(x+5)), so:

2-(x+5)

determiningTheFunctionDomain
-(x+5)+2

We get rid of parentheses

-x-5+2

We add all the numbers together, and all the variables

-1x-3

Back to the equation:

-(-1x-3)



We get rid of parentheses

10x+1x+3-20=0

We add all the numbers together, and all the variables

11x-17=0

We move all terms containing x to the left, all other terms to the right

11x=17

x=17/11

x=1+6/11

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