10(x-2)=5(2x-5)+5

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Solution for 10(x-2)=5(2x-5)+5 equation:


Simplifying
10(x + -2) = 5(2x + -5) + 5

Reorder the terms:
10(-2 + x) = 5(2x + -5) + 5
(-2 * 10 + x * 10) = 5(2x + -5) + 5
(-20 + 10x) = 5(2x + -5) + 5

Reorder the terms:
-20 + 10x = 5(-5 + 2x) + 5
-20 + 10x = (-5 * 5 + 2x * 5) + 5
-20 + 10x = (-25 + 10x) + 5

Reorder the terms:
-20 + 10x = -25 + 5 + 10x

Combine like terms: -25 + 5 = -20
-20 + 10x = -20 + 10x

Add '20' to each side of the equation.
-20 + 20 + 10x = -20 + 20 + 10x

Combine like terms: -20 + 20 = 0
0 + 10x = -20 + 20 + 10x
10x = -20 + 20 + 10x

Combine like terms: -20 + 20 = 0
10x = 0 + 10x
10x = 10x

Add '-10x' to each side of the equation.
10x + -10x = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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