10(x-20)+3(-12x+1)-(126x+42)=-57(x+1256)

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Solution for 10(x-20)+3(-12x+1)-(126x+42)=-57(x+1256) equation: 



10(x-20)+3(-12x+1)-(126x+42)=-57(x+1256)

We move all terms to the left:

10(x-20)+3(-12x+1)-(126x+42)-(-57(x+1256))=0

We multiply parentheses

10x-36x-(126x+42)-(-57(x+1256))-200+3=0

We get rid of parentheses

10x-36x-126x-(-57(x+1256))-42-200+3=0



We calculate terms in parentheses: -(-57(x+1256)), so:

-57(x+1256)

We multiply parentheses

-57x-71592

Back to the equation:

-(-57x-71592)



We add all the numbers together, and all the variables

-152x-(-57x-71592)-239=0

We get rid of parentheses

-152x+57x+71592-239=0

We add all the numbers together, and all the variables

-95x+71353=0

We move all terms containing x to the left, all other terms to the right

-95x=-71353

x=-71353/-95

x=751+8/95

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