10(x-3)+34=4(x-7)+80

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Solution for 10(x-3)+34=4(x-7)+80 equation: 



10(x-3)+34=4(x-7)+80

We move all terms to the left:

10(x-3)+34-(4(x-7)+80)=0

We multiply parentheses

10x-(4(x-7)+80)-30+34=0



We calculate terms in parentheses: -(4(x-7)+80), so:

4(x-7)+80

We multiply parentheses

4x-28+80

We add all the numbers together, and all the variables

4x+52

Back to the equation:

-(4x+52)



We add all the numbers together, and all the variables

10x-(4x+52)+4=0

We get rid of parentheses

10x-4x-52+4=0

We add all the numbers together, and all the variables

6x-48=0

We move all terms containing x to the left, all other terms to the right

6x=48

x=48/6

x=8

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