10(x-3)-2(6-2x)=5(4+2x)+18

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Solution for 10(x-3)-2(6-2x)=5(4+2x)+18 equation: 



10(x-3)-2(6-2x)=5(4+2x)+18

We move all terms to the left:

10(x-3)-2(6-2x)-(5(4+2x)+18)=0

We add all the numbers together, and all the variables

10(x-3)-2(-2x+6)-(5(2x+4)+18)=0

We multiply parentheses

10x+4x-(5(2x+4)+18)-30-12=0



We calculate terms in parentheses: -(5(2x+4)+18), so:

5(2x+4)+18

We multiply parentheses

10x+20+18

We add all the numbers together, and all the variables

10x+38

Back to the equation:

-(10x+38)



We add all the numbers together, and all the variables

14x-(10x+38)-42=0

We get rid of parentheses

14x-10x-38-42=0

We add all the numbers together, and all the variables

4x-80=0

We move all terms containing x to the left, all other terms to the right

4x=80

x=80/4

x=20

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