10(x-3)=2(x+5)

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Solution for 10(x-3)=2(x+5) equation: 



10(x-3)=2(x+5)

We move all terms to the left:

10(x-3)-(2(x+5))=0

We multiply parentheses

10x-(2(x+5))-30=0



We calculate terms in parentheses: -(2(x+5)), so:

2(x+5)

We multiply parentheses

2x+10

Back to the equation:

-(2x+10)



We get rid of parentheses

10x-2x-10-30=0

We add all the numbers together, and all the variables

8x-40=0

We move all terms containing x to the left, all other terms to the right

8x=40

x=40/8

x=5

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