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10(x-3)=2(x+5)
We move all terms to the left:
10(x-3)-(2(x+5))=0
We multiply parentheses
10x-(2(x+5))-30=0
We calculate terms in parentheses: -(2(x+5)), so:We get rid of parentheses
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
10x-2x-10-30=0
We add all the numbers together, and all the variables
8x-40=0
We move all terms containing x to the left, all other terms to the right
8x=40
x=40/8
x=5
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