10(x-4)+2(x-5)-5(x+16)=19

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Solution for 10(x-4)+2(x-5)-5(x+16)=19 equation:



10(x-4)+2(x-5)-5(x+16)=19
We move all terms to the left:
10(x-4)+2(x-5)-5(x+16)-(19)=0
We multiply parentheses
10x+2x-5x-40-10-80-19=0
We add all the numbers together, and all the variables
7x-149=0
We move all terms containing x to the left, all other terms to the right
7x=149
x=149/7
x=21+2/7

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