10(x-4)+2(x-5)-5(x+16)=19

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Solution for 10(x-4)+2(x-5)-5(x+16)=19 equation: 



10(x-4)+2(x-5)-5(x+16)=19

We move all terms to the left:

10(x-4)+2(x-5)-5(x+16)-(19)=0

We multiply parentheses

10x+2x-5x-40-10-80-19=0

We add all the numbers together, and all the variables

7x-149=0

We move all terms containing x to the left, all other terms to the right

7x=149

x=149/7

x=21+2/7

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