10(x-4)=-2x+32

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Solution for 10(x-4)=-2x+32 equation: 



10(x-4)=-2x+32

We move all terms to the left:

10(x-4)-(-2x+32)=0

We multiply parentheses

10x-(-2x+32)-40=0

We get rid of parentheses

10x+2x-32-40=0

We add all the numbers together, and all the variables

12x-72=0

We move all terms containing x to the left, all other terms to the right

12x=72

x=72/12

x=6

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