10(x-4)=4(x+4)+4(x-2)

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Solution for 10(x-4)=4(x+4)+4(x-2) equation: 



10(x-4)=4(x+4)+4(x-2)

We move all terms to the left:

10(x-4)-(4(x+4)+4(x-2))=0

We multiply parentheses

10x-(4(x+4)+4(x-2))-40=0



We calculate terms in parentheses: -(4(x+4)+4(x-2)), so:

4(x+4)+4(x-2)

We multiply parentheses

4x+4x+16-8

We add all the numbers together, and all the variables

8x+8

Back to the equation:

-(8x+8)



We get rid of parentheses

10x-8x-8-40=0

We add all the numbers together, and all the variables

2x-48=0

We move all terms containing x to the left, all other terms to the right

2x=48

x=48/2

x=24

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