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10(x-4)=5(x+3)
We move all terms to the left:
10(x-4)-(5(x+3))=0
We multiply parentheses
10x-(5(x+3))-40=0
We calculate terms in parentheses: -(5(x+3)), so:We get rid of parentheses
5(x+3)
We multiply parentheses
5x+15
Back to the equation:
-(5x+15)
10x-5x-15-40=0
We add all the numbers together, and all the variables
5x-55=0
We move all terms containing x to the left, all other terms to the right
5x=55
x=55/5
x=11
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