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10(x-4)=5(x+5)
We move all terms to the left:
10(x-4)-(5(x+5))=0
We multiply parentheses
10x-(5(x+5))-40=0
We calculate terms in parentheses: -(5(x+5)), so:We get rid of parentheses
5(x+5)
We multiply parentheses
5x+25
Back to the equation:
-(5x+25)
10x-5x-25-40=0
We add all the numbers together, and all the variables
5x-65=0
We move all terms containing x to the left, all other terms to the right
5x=65
x=65/5
x=13
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