10(x-5)=4x+21

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Solution for 10(x-5)=4x+21 equation: 



10(x-5)=4x+21

We move all terms to the left:

10(x-5)-(4x+21)=0

We multiply parentheses

10x-(4x+21)-50=0

We get rid of parentheses

10x-4x-21-50=0

We add all the numbers together, and all the variables

6x-71=0

We move all terms containing x to the left, all other terms to the right

6x=71

x=71/6

x=11+5/6

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