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10(x-5)=5(x-3)
We move all terms to the left:
10(x-5)-(5(x-3))=0
We multiply parentheses
10x-(5(x-3))-50=0
We calculate terms in parentheses: -(5(x-3)), so:We get rid of parentheses
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
10x-5x+15-50=0
We add all the numbers together, and all the variables
5x-35=0
We move all terms containing x to the left, all other terms to the right
5x=35
x=35/5
x=7
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