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10(x-5)=7(x+4)
We move all terms to the left:
10(x-5)-(7(x+4))=0
We multiply parentheses
10x-(7(x+4))-50=0
We calculate terms in parentheses: -(7(x+4)), so:We get rid of parentheses
7(x+4)
We multiply parentheses
7x+28
Back to the equation:
-(7x+28)
10x-7x-28-50=0
We add all the numbers together, and all the variables
3x-78=0
We move all terms containing x to the left, all other terms to the right
3x=78
x=78/3
x=26
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