10(x-7)=2x+55+3x+65

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Solution for 10(x-7)=2x+55+3x+65 equation:



10(x-7)=2x+55+3x+65
We move all terms to the left:
10(x-7)-(2x+55+3x+65)=0
We add all the numbers together, and all the variables
10(x-7)-(5x+120)=0
We multiply parentheses
10x-(5x+120)-70=0
We get rid of parentheses
10x-5x-120-70=0
We add all the numbers together, and all the variables
5x-190=0
We move all terms containing x to the left, all other terms to the right
5x=190
x=190/5
x=38

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