10(x/5-2)-12(3x/4-3)=-(x+8)

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Solution for 10(x/5-2)-12(3x/4-3)=-(x+8) equation: 


x in (-oo:+oo)

10*(x/5-2)-(12*((3*x)/4-3)) = -(x+8) // + x+8

10*(x/5-2)-(12*((3*x)/4-3))+x+8 = 0

10*(x/5-2)-12*((3*x)/4-3)+x+8 = 0

10*(1/5*x-2)-12*(3/4*x-3)+x+8 = 0

10*(1/5*x-2)-12*(3/4*x-3)+x+8 = 0

x-7*x+8+16 = 0

8-6*x+16 = 0

24-6*x = 0

24-6*x = 0

24-6*x = 0 // - 24

-6*x = -24 // : -6

x = -24/(-6)

x = 4

x = 4

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