10(y+2)-4y=2(3y+4)-14

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Solution for 10(y+2)-4y=2(3y+4)-14 equation: 


Simplifying
10(y + 2) + -4y = 2(3y + 4) + -14

Reorder the terms:
10(2 + y) + -4y = 2(3y + 4) + -14
(2 * 10 + y * 10) + -4y = 2(3y + 4) + -14
(20 + 10y) + -4y = 2(3y + 4) + -14

Combine like terms: 10y + -4y = 6y
20 + 6y = 2(3y + 4) + -14

Reorder the terms:
20 + 6y = 2(4 + 3y) + -14
20 + 6y = (4 * 2 + 3y * 2) + -14
20 + 6y = (8 + 6y) + -14

Reorder the terms:
20 + 6y = 8 + -14 + 6y

Combine like terms: 8 + -14 = -6
20 + 6y = -6 + 6y

Add '-6y' to each side of the equation.
20 + 6y + -6y = -6 + 6y + -6y

Combine like terms: 6y + -6y = 0
20 + 0 = -6 + 6y + -6y
20 = -6 + 6y + -6y

Combine like terms: 6y + -6y = 0
20 = -6 + 0
20 = -6

Solving
20 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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