10(y+2)=6(y+2)+16

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Solution for 10(y+2)=6(y+2)+16 equation: 



10(y+2)=6(y+2)+16

We move all terms to the left:

10(y+2)-(6(y+2)+16)=0

We multiply parentheses

10y-(6(y+2)+16)+20=0



We calculate terms in parentheses: -(6(y+2)+16), so:

6(y+2)+16

We multiply parentheses

6y+12+16

We add all the numbers together, and all the variables

6y+28

Back to the equation:

-(6y+28)



We get rid of parentheses

10y-6y-28+20=0

We add all the numbers together, and all the variables

4y-8=0

We move all terms containing y to the left, all other terms to the right

4y=8

y=8/4

y=2

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