10(y+3)-6(y+1)=2y

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Solution for 10(y+3)-6(y+1)=2y equation: 



10(y+3)-6(y+1)=2y

We move all terms to the left:

10(y+3)-6(y+1)-(2y)=0

We add all the numbers together, and all the variables

-2y+10(y+3)-6(y+1)=0

We multiply parentheses

-2y+10y-6y+30-6=0

We add all the numbers together, and all the variables

2y+24=0

We move all terms containing y to the left, all other terms to the right

2y=-24

y=-24/2

y=-12

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