10(y+4)+3y=27

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Solution for 10(y+4)+3y=27 equation: 



10(y+4)+3y=27

We move all terms to the left:

10(y+4)+3y-(27)=0

We add all the numbers together, and all the variables

3y+10(y+4)-27=0

We multiply parentheses

3y+10y+40-27=0

We add all the numbers together, and all the variables

13y+13=0

We move all terms containing y to the left, all other terms to the right

13y=-13

y=-13/13

y=-1

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