10(y+4)=5(3y-80)

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Solution for 10(y+4)=5(3y-80) equation: 



10(y+4)=5(3y-80)

We move all terms to the left:

10(y+4)-(5(3y-80))=0

We multiply parentheses

10y-(5(3y-80))+40=0



We calculate terms in parentheses: -(5(3y-80)), so:

5(3y-80)

We multiply parentheses

15y-400

Back to the equation:

-(15y-400)



We get rid of parentheses

10y-15y+400+40=0

We add all the numbers together, and all the variables

-5y+440=0

We move all terms containing y to the left, all other terms to the right

-5y=-440

y=-440/-5

y=+88

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