10(y+9)/11=9(y-12)/10

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Solution for 10(y+9)/11=9(y-12)/10 equation: 



10(y+9)/11=9(y-12)/10

We move all terms to the left:

10(y+9)/11-(9(y-12)/10)=0

We calculate fractions


10y/()+(-(9(y-12)*11)/()=0



We calculate terms in parentheses: +(-(9(y-12)*11)/(), so:

-(9(y-12)*11)/(

We multiply all the terms by the denominator


-(9(y-12)*11)



We calculate terms in parentheses: -(9(y-12)*11), so:

9(y-12)*11

We multiply parentheses

99y-1188

Back to the equation:

-(99y-1188)



We get rid of parentheses

-99y+1188

Back to the equation:

+(-99y+1188)



We get rid of parentheses

10y/()-99y+1188=0

We multiply all the terms by the denominator


10y-99y*()+1188*()=0

We add all the numbers together, and all the variables

10y-99y*()=0

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