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10(y-2)=2(y+4)
We move all terms to the left:
10(y-2)-(2(y+4))=0
We multiply parentheses
10y-(2(y+4))-20=0
We calculate terms in parentheses: -(2(y+4)), so:We get rid of parentheses
2(y+4)
We multiply parentheses
2y+8
Back to the equation:
-(2y+8)
10y-2y-8-20=0
We add all the numbers together, and all the variables
8y-28=0
We move all terms containing y to the left, all other terms to the right
8y=28
y=28/8
y=3+1/2
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