10(z+1)=5(z-3)

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Solution for 10(z+1)=5(z-3) equation:



10(z+1)=5(z-3)
We move all terms to the left:
10(z+1)-(5(z-3))=0
We multiply parentheses
10z-(5(z-3))+10=0
We calculate terms in parentheses: -(5(z-3)), so:
5(z-3)
We multiply parentheses
5z-15
Back to the equation:
-(5z-15)
We get rid of parentheses
10z-5z+15+10=0
We add all the numbers together, and all the variables
5z+25=0
We move all terms containing z to the left, all other terms to the right
5z=-25
z=-25/5
z=-5

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