10(z+1)=5(z-3)

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Solution for 10(z+1)=5(z-3) equation: 



10(z+1)=5(z-3)

We move all terms to the left:

10(z+1)-(5(z-3))=0

We multiply parentheses

10z-(5(z-3))+10=0



We calculate terms in parentheses: -(5(z-3)), so:

5(z-3)

We multiply parentheses

5z-15

Back to the equation:

-(5z-15)



We get rid of parentheses

10z-5z+15+10=0

We add all the numbers together, and all the variables

5z+25=0

We move all terms containing z to the left, all other terms to the right

5z=-25

z=-25/5

z=-5

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