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10(z+3)-4(z-2)=2(z-1)+3(z-2)
We move all terms to the left:
10(z+3)-4(z-2)-(2(z-1)+3(z-2))=0
We multiply parentheses
10z-4z-(2(z-1)+3(z-2))+30+8=0
We calculate terms in parentheses: -(2(z-1)+3(z-2)), so:We add all the numbers together, and all the variables
2(z-1)+3(z-2)
We multiply parentheses
2z+3z-2-6
We add all the numbers together, and all the variables
5z-8
Back to the equation:
-(5z-8)
6z-(5z-8)+38=0
We get rid of parentheses
6z-5z+8+38=0
We add all the numbers together, and all the variables
z+46=0
We move all terms containing z to the left, all other terms to the right
z=-46
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