10(z+3)-8z=34

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Solution for 10(z+3)-8z=34 equation: 



10(z+3)-8z=34

We move all terms to the left:

10(z+3)-8z-(34)=0

We add all the numbers together, and all the variables

-8z+10(z+3)-34=0

We multiply parentheses

-8z+10z+30-34=0

We add all the numbers together, and all the variables

2z-4=0

We move all terms containing z to the left, all other terms to the right

2z=4

z=4/2

z=2

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