10(z+3)=4(2z+9)+4z

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Solution for 10(z+3)=4(2z+9)+4z equation: 



10(z+3)=4(2z+9)+4z

We move all terms to the left:

10(z+3)-(4(2z+9)+4z)=0

We multiply parentheses

10z-(4(2z+9)+4z)+30=0



We calculate terms in parentheses: -(4(2z+9)+4z), so:

4(2z+9)+4z

We add all the numbers together, and all the variables

4z+4(2z+9)

We multiply parentheses

4z+8z+36

We add all the numbers together, and all the variables

12z+36

Back to the equation:

-(12z+36)



We get rid of parentheses

10z-12z-36+30=0

We add all the numbers together, and all the variables

-2z-6=0

We move all terms containing z to the left, all other terms to the right

-2z=6

z=6/-2

z=-3

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