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10(z+4)-2(z-2)=4(z-1)+3(z-2)
We move all terms to the left:
10(z+4)-2(z-2)-(4(z-1)+3(z-2))=0
We multiply parentheses
10z-2z-(4(z-1)+3(z-2))+40+4=0
We calculate terms in parentheses: -(4(z-1)+3(z-2)), so:We add all the numbers together, and all the variables
4(z-1)+3(z-2)
We multiply parentheses
4z+3z-4-6
We add all the numbers together, and all the variables
7z-10
Back to the equation:
-(7z-10)
8z-(7z-10)+44=0
We get rid of parentheses
8z-7z+10+44=0
We add all the numbers together, and all the variables
z+54=0
We move all terms containing z to the left, all other terms to the right
z=-54
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