10(z+4)-4(z-2)=3(z+2(z-3)

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Solution for 10(z+4)-4(z-2)=3(z+2(z-3) equation: 



10(z+4)-4(z-2)=3(z+2(z-3)

We move all terms to the left:

10(z+4)-4(z-2)-(3(z+2(z-3))=0

We multiply parentheses

10z-4z-(3(z+2(z-3))+40+8=0

We add all the numbers together, and all the variables

6z-(3(z+2(z-3))+40+8=0

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