10(z-2)+10-2z=8(z+1)-18

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Solution for 10(z-2)+10-2z=8(z+1)-18 equation:


Simplifying
10(z + -2) + 10 + -2z = 8(z + 1) + -18

Reorder the terms:
10(-2 + z) + 10 + -2z = 8(z + 1) + -18
(-2 * 10 + z * 10) + 10 + -2z = 8(z + 1) + -18
(-20 + 10z) + 10 + -2z = 8(z + 1) + -18

Reorder the terms:
-20 + 10 + 10z + -2z = 8(z + 1) + -18

Combine like terms: -20 + 10 = -10
-10 + 10z + -2z = 8(z + 1) + -18

Combine like terms: 10z + -2z = 8z
-10 + 8z = 8(z + 1) + -18

Reorder the terms:
-10 + 8z = 8(1 + z) + -18
-10 + 8z = (1 * 8 + z * 8) + -18
-10 + 8z = (8 + 8z) + -18

Reorder the terms:
-10 + 8z = 8 + -18 + 8z

Combine like terms: 8 + -18 = -10
-10 + 8z = -10 + 8z

Add '10' to each side of the equation.
-10 + 10 + 8z = -10 + 10 + 8z

Combine like terms: -10 + 10 = 0
0 + 8z = -10 + 10 + 8z
8z = -10 + 10 + 8z

Combine like terms: -10 + 10 = 0
8z = 0 + 8z
8z = 8z

Add '-8z' to each side of the equation.
8z + -8z = 8z + -8z

Combine like terms: 8z + -8z = 0
0 = 8z + -8z

Combine like terms: 8z + -8z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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