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10*(1/2)x-3=97
We move all terms to the left:
10*(1/2)x-3-(97)=0
Domain of the equation: 2)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
10*(+1/2)x-3-97=0
We add all the numbers together, and all the variables
10*(+1/2)x-100=0
We multiply parentheses
10x^2-100=0
a = 10; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·10·(-100)
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{10}}{2*10}=\frac{0-20\sqrt{10}}{20} =-\frac{20\sqrt{10}}{20} =-\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{10}}{2*10}=\frac{0+20\sqrt{10}}{20} =\frac{20\sqrt{10}}{20} =\sqrt{10} $
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