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10(x+9)-3x-140=6x-2-5x+3x
We move all terms to the left:
10(x+9)-3x-140-(6x-2-5x+3x)=0
We add all the numbers together, and all the variables
10(x+9)-3x-(4x-2)-140=0
We add all the numbers together, and all the variables
-3x+10(x+9)-(4x-2)-140=0
We multiply parentheses
-3x+10x-(4x-2)+90-140=0
We get rid of parentheses
-3x+10x-4x+2+90-140=0
We add all the numbers together, and all the variables
3x-48=0
We move all terms containing x to the left, all other terms to the right
3x=48
x=48/3
x=16
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