10+((2-x)/3)=7

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Solution for 10+((2-x)/3)=7 equation: 



10+((2-x)/3)=7

We move all terms to the left:

10+((2-x)/3)-(7)=0

We add all the numbers together, and all the variables

((-1x+2)/3)+10-7=0

We add all the numbers together, and all the variables

((-1x+2)/3)+3=0

We multiply all the terms by the denominator


((-1x+2)+3*3)=0



We calculate terms in parentheses: +((-1x+2)+3*3), so:

(-1x+2)+3*3

We add all the numbers together, and all the variables

(-1x+2)+9

We get rid of parentheses

-1x+2+9

We add all the numbers together, and all the variables

-1x+11

Back to the equation:

+(-1x+11)



We get rid of parentheses

-1x+11=0

We move all terms containing x to the left, all other terms to the right

-x=-11

x=-11/-1

x=+11

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