10+(16-4x)=30-(6x-2)

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Solution for 10+(16-4x)=30-(6x-2) equation: 



10+(16-4x)=30-(6x-2)

We move all terms to the left:

10+(16-4x)-(30-(6x-2))=0

We add all the numbers together, and all the variables

(-4x+16)-(30-(6x-2))+10=0

We get rid of parentheses

-4x-(30-(6x-2))+16+10=0



We calculate terms in parentheses: -(30-(6x-2)), so:

30-(6x-2)

determiningTheFunctionDomain
-(6x-2)+30

We get rid of parentheses

-6x+2+30

We add all the numbers together, and all the variables

-6x+32

Back to the equation:

-(-6x+32)



We add all the numbers together, and all the variables

-4x-(-6x+32)+26=0

We get rid of parentheses

-4x+6x-32+26=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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