10+(2/3)*(3-7x)=-(1/3)x+3

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Solution for 10+(2/3)*(3-7x)=-(1/3)x+3 equation: 



10+(2/3)(3-7x)=-(1/3)x+3

We move all terms to the left:

10+(2/3)(3-7x)-(-(1/3)x+3)=0



Domain of the equation: 3)(3-7x)!=0

x∈R





Domain of the equation: 3)x+3)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)(-7x+3)-(-(+1/3)x+3)+10=0

We multiply parentheses ..

(-14x^2+2/3*3)-(-(+1/3)x+3)+10=0

We calculate fractions

We do not support expression: x^3

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