10+(2/3*x)=1x

Solution for 10+(2/3*x)=1x equation:

10+(2/3x)=1x

We move all terms to the left:

10+(2/3x)-(1x)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3x)-1x+10=0

We add all the numbers together, and all the variables

-1x+(+2/3x)+10=0

We get rid of parentheses

-1x+2/3x+10=0

We multiply all the terms by the denominator


-1x*3x+10*3x+2=0

Wy multiply elements

-3x^2+30x+2=0

a = -3; b = 30; c = +2;
Δ = b2-4ac
Δ = 302-4·(-3)·2
Δ = 924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{924}=\sqrt{4*231}=\sqrt{4}*\sqrt{231}=2\sqrt{231}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{231}}{2*-3}=\frac{-30-2\sqrt{231}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{231}}{2*-3}=\frac{-30+2\sqrt{231}}{-6}
$