10+(8-x)=10x+5(1-x)

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Solution for 10+(8-x)=10x+5(1-x) equation: 



10+(8-x)=10x+5(1-x)

We move all terms to the left:

10+(8-x)-(10x+5(1-x))=0

We add all the numbers together, and all the variables

(-1x+8)-(10x+5(-1x+1))+10=0

We get rid of parentheses

-1x-(10x+5(-1x+1))+8+10=0



We calculate terms in parentheses: -(10x+5(-1x+1)), so:

10x+5(-1x+1)

We multiply parentheses

10x-5x+5

We add all the numbers together, and all the variables

5x+5

Back to the equation:

-(5x+5)



We add all the numbers together, and all the variables

-1x-(5x+5)+18=0

We get rid of parentheses

-1x-5x-5+18=0

We add all the numbers together, and all the variables

-6x+13=0

We move all terms containing x to the left, all other terms to the right

-6x=-13

x=-13/-6

x=2+1/6

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