10+(x+1)-6=2(x+3)-10

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Solution for 10+(x+1)-6=2(x+3)-10 equation: 



10+(x+1)-6=2(x+3)-10

We move all terms to the left:

10+(x+1)-6-(2(x+3)-10)=0

We add all the numbers together, and all the variables

(x+1)-(2(x+3)-10)+4=0

We get rid of parentheses

x-(2(x+3)-10)+1+4=0



We calculate terms in parentheses: -(2(x+3)-10), so:

2(x+3)-10

We multiply parentheses

2x+6-10

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

x-(2x-4)+5=0

We get rid of parentheses

x-2x+4+5=0

We add all the numbers together, and all the variables

-1x+9=0

We move all terms containing x to the left, all other terms to the right

-x=-9

x=-9/-1

x=+9

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