10+0.5(4y-6)=-2(4-11y)-5

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Solution for 10+0.5(4y-6)=-2(4-11y)-5 equation: 



10+0.5(4y-6)=-2(4-11y)-5

We move all terms to the left:

10+0.5(4y-6)-(-2(4-11y)-5)=0

We add all the numbers together, and all the variables

0.5(4y-6)-(-2(-11y+4)-5)+10=0

We multiply parentheses

2y-(-2(-11y+4)-5)-3+10=0



We calculate terms in parentheses: -(-2(-11y+4)-5), so:

-2(-11y+4)-5

We multiply parentheses

22y-8-5

We add all the numbers together, and all the variables

22y-13

Back to the equation:

-(22y-13)



We add all the numbers together, and all the variables

2y-(22y-13)+7=0

We get rid of parentheses

2y-22y+13+7=0

We add all the numbers together, and all the variables

-20y+20=0

We move all terms containing y to the left, all other terms to the right

-20y=-20

y=-20/-20

y=1

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