10+11/x=-40+x

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Solution for 10+11/x=-40+x equation:



10+11/x=-40+x
We move all terms to the left:
10+11/x-(-40+x)=0
Domain of the equation: x!=0
x∈R
We add all the numbers together, and all the variables
11/x-(x-40)+10=0
We get rid of parentheses
11/x-x+40+10=0
We multiply all the terms by the denominator
-x*x+40*x+10*x+11=0
We add all the numbers together, and all the variables
50x-x*x+11=0
Wy multiply elements
-1x^2+50x+11=0
a = -1; b = 50; c = +11;
Δ = b2-4ac
Δ = 502-4·(-1)·11
Δ = 2544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2544}=\sqrt{16*159}=\sqrt{16}*\sqrt{159}=4\sqrt{159}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-4\sqrt{159}}{2*-1}=\frac{-50-4\sqrt{159}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+4\sqrt{159}}{2*-1}=\frac{-50+4\sqrt{159}}{-2} $

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