10+19=29x2

Solution for 10+19=29x2 equation:

10+19=29x^2

We move all terms to the left:

10+19-(29x^2)=0

We add all the numbers together, and all the variables

-29x^2+29=0

a = -29; b = 0; c = +29;
Δ = b2-4ac
Δ = 02-4·(-29)·29
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-58}{2*-29}=\frac{-58}{-58}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+58}{2*-29}=\frac{58}{-58}
=-1
$