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10+19=29x^2
We move all terms to the left:
10+19-(29x^2)=0
We add all the numbers together, and all the variables
-29x^2+29=0
a = -29; b = 0; c = +29;
Δ = b2-4ac
Δ = 02-4·(-29)·29
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-58}{2*-29}=\frac{-58}{-58} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+58}{2*-29}=\frac{58}{-58} =-1 $
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