10+2(3x-4)=2(4-x)-4

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Solution for 10+2(3x-4)=2(4-x)-4 equation: 



10+2(3x-4)=2(4-x)-4

We move all terms to the left:

10+2(3x-4)-(2(4-x)-4)=0

We add all the numbers together, and all the variables

2(3x-4)-(2(-1x+4)-4)+10=0

We multiply parentheses

6x-(2(-1x+4)-4)-8+10=0



We calculate terms in parentheses: -(2(-1x+4)-4), so:

2(-1x+4)-4

We multiply parentheses

-2x+8-4

We add all the numbers together, and all the variables

-2x+4

Back to the equation:

-(-2x+4)



We add all the numbers together, and all the variables

6x-(-2x+4)+2=0

We get rid of parentheses

6x+2x-4+2=0

We add all the numbers together, and all the variables

8x-2=0

We move all terms containing x to the left, all other terms to the right

8x=2

x=2/8

x=1/4

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